a.b.c.d/e is a "new" notation ("CIDR") used to identify a netblock. It
identifies a network beginning at a.b.c.d where e bytes are the network
portion. There's an RFC that covers this in depth, but the old-style
A,B,C networks are /8, /16, /24 respectively. A slight
overapproximation of the maximum number of hosts on a /e network is
2**(31-e). An IP address is 32 bits, e of which identify the network.
So, 32-e of them identify the host. There are 2**n possible ways to set
n bits (and the maximum value of n bits is 2**(n-1)).
Probably the other post was right and your friend has used a netmask
appropriate for a /e network.
Justin
On Tue, Jul 29, 2003 at 08:25:03PM +0000, chris halverson wrote:
>
> I am not sure what you are asking when you refer to the 2**8 - 1 addresses.
> Can you clarify?
>
>
>
> >From: Justin Pryzby <[EMAIL PROTECTED]>
> >To: Vineet Mehta <[EMAIL PROTECTED]>,[EMAIL PROTECTED]
> >Subject: Re: 2NIC's on same network, possible?
> >Date: Mon, 28 Jul 2003 17:08:37 -0700
> >
> >That should definitely be possible, though I don't know how it will
> >decide which NIC to use for what. What do you mean '192.168.0.6/24'? A
> >NIC has an address, and that notation represents 2**8 - 1 addresses.
> >Justin
> >
> >On Tue, Jul 29, 2003 at 03:04:04AM +0000, Vineet Mehta wrote:
> > >
> > >
> > > Hi all,
> > >
> > > My collegue has a Linux machine which has 2 NIC's on it. What he did was
> > > assign the IP's 192.168.0.6/24 and 192.168.0.7/24 to the NIC's. And he
> > > was trying to ping the network but was getting errors (i dont know the
> > > errors).
> >
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