On Tue, 6 Sep 2022 17:53:32 GMT, Weijun Wang <[email protected]> wrote:
>> src/java.base/share/classes/sun/security/provider/PolicyParser.java line
>> 1180:
>>
>>> 1178: // and then in a java string, it's escaped again
>>> 1179:
>>> 1180: out.print(name.replaceAll("\\\\",
>>> "\\\\\\\\").replaceAll("\"", "\\\\\\\""));
>>
>> Why does IJ say this is the same? This appears to replace backslash-quote
>> with quote.
>
> My understanding: In regex, there is no need to escape `"`, so `"` is the
> same as `"`.
Ok,but the regex is `"\\""`, so shouldn't it keep the double-backslash at the
beginning (`\`)?, i.e.:
`...replaceAll("\"", "\\\\\\""));`
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PR: https://git.openjdk.org/jdk/pull/9972
