This way of setting the Provider using the JCEMapper, has some bugs(it
works for digesting/signing but not for crypt/decrypt).
Anyway I was thinking of deprecating/removing this methods.
So if more people use it please raise your hands, soon.
On 10/22/05, Werner Dittmann <[EMAIL PROTECTED]> wrote:
> In WSS4J I use the follwing way to define the provider to XML-SEC:
>
> JCEMapper.setProviderId(id)
>
> This static method sets the Id to use for SIgnature etc. For
> XMLCipher you must use different methods, look at that:
>
> if (provider == null) {
> xmlCipher = XMLCipher.getInstance(symEncAlgo);
> }
> else {
> xmlCipher = XMLCipher.getProviderInstance(symEncAlgo, provider);
> }
>
> If you like to specify a provider for XMLCipher you have
> to use a specific getInstance method - see above. The provider
> in this case is the provider id string, e.g. "BC" for
> BouncyCastle.
>
> regards,
> Werner
>
>
>
> Raul Benito wrote:
> > This provider.properties is a relic of the old days. Right now is not
> > used anymore. (TODO: remove it from the CVS).
> > Right now the xml-sec use the standard java way of getting a JCE Provider.
> > Look at
> > http://java.sun.com/j2se/1.4.2/docs/guide/security/CryptoSpec.html#Provider
> > for more info.
> >
> > Regards,
> >
> > Raul
> >
> > On 10/22/05, Alexey <[EMAIL PROTECTED]> wrote:
> >
> >>Hello,
> >>Can anybody please, navigate me through the process? We're using various JCE
> >>providers, such as SunJCE, IBMJCE. How do I specify particaluar provider
> >>and/or
> >>cipher algorithm? Any changes I make to config.xml are ignored and, after
> >>checking the source code I don't see how the following element can be
> >>processed
> >>(ProviderAlgo). Browsing CVS I came across a file called
> >>provider.properties. Is
> >>this a way to specify my provider? If so where should I put it, please?
> >>
> >><Algorithm URI="http://www.w3.org/2001/04/xmlenc#rsa-1_5";
> >> Description="Key Transport RSA-v1.5">
> >> <ProviderAlgo ProviderId="IBMJCE" JCEName="RSA"/>
> >></Algorithm>
> >>
> >>Javadocs say that I can get an instance of an XML cipher via
> >>XMLCipher.getInstance() and use it as a "generic" cipher for decryption. But
> >>when I try to initialize it with my key (which carries algorithm
> >>information) I
> >>am getting exception:
> >>
> >>org.apache.xml.security.encryption.XMLEncryptionException: No message with
> >>ID
> >>"XMLCipher instance without transformation specified" found in resource
> >>bundle
> >>"org/apache/xml/security/resource/xmlsecurity"
> >>
> >>Is it possible to re-use a cipher for different algorithms?
> >>
> >>Thanks,
> >>Alexey
> >>
> >>
> >>
> >
> >
> >
> > --
> > http://r-bg.com
> >
>
>
--
http://r-bg.com
