Le 2012-11-22 à 11:20, Vaggelis Typaldos a écrit :
> # FAKE Sequel connestion string that includes hash characters in psswd
> schema = 'SCHEMA_FAKE'
> psswd = 'aaa###bbbccc'
> host = 'my.host.el'
> port = '1521'
> sid = 'SIDDB'
> conn_string = "oracle://#{ schema }" + ':' + psswd + '@' + host + ':' + port
> + '/' + sid
>
> The returning error:
>
> C:/Ruby193/lib/ruby/1.9.1/uri/common.rb:176:in `split': bad URI(is not URI?):
> oracle://SCHEMA_FAKE:aaa###[email protected]:1521/SIDDB (URI::InvalidURIError)
> from C:/Ruby193/lib/ruby/1.9.1/uri/common.rb:211:in `parse'
> from C:/Ruby193/lib/ruby/1.9.1/uri/common.rb:747:in `parse'
> from
> C:/Ruby193/lib/ruby/gems/1.9.1/gems/sequel-3.41.0/lib/sequel/database/connecting.rb:52:in
> `connect'
> from
> C:/Ruby193/lib/ruby/gems/1.9.1/gems/sequel-3.41.0/lib/sequel/core.rb:147:in
> `connect'
> from C:/Users/etypaldos/Desktop/prod-wrk.rb:35:in `<main>'
> [Finished in 0.2s with exit code 1]
>
>
> This is due to lib/sequel/database/connecting.rb: in line 52:
> uri = URI.parse(conn_string)
That's not a Sequel bug, you are in error. You must pass a well-formed URI. You
are passing in a wrongly formatted URI, hence you should fix the caller, not
the callee.
Bye,
François
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