Regarding the timing of subsequent tries to overcome network failures, I have seen the phrase "exponential backoff strategy" used. I thought I had seen that in RFC 2821. But if it were there I expect Noel would have reported it.

As I understand it, the delays in an exponential backoff strategy would be computed as in the following example.

If the goal is to have 5 retries which end after 5 days, then my calculator says the first delay should be about 13.4 seconds (5 days)**(1/5). (Where ** means "raised to the power of".)

13.4**1 =      13 ~= 13 seconds
13.4**2 =     180 ~= 3 minutes
13.4**3 =   2,406 ~= 40 minutes
13.4**4 =  32,242 ~= 9 hours
13.4**5 = 432,040 ~= 5 days

Rich Hammer
Hillsborough, N.C.




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