Hi,
I am using servletrunner (on NT) to run my servlet and my servlet
can't seem to access extenal resourcs.I am trying to open a file which
is in the same default directory .\examples\ as my servlet and for some
reason it cannot open the file,I get an exception.
I am also not able to pass any init parameters to my servlet. I
have pasted my servlet.properties file below. My servlet- MainServlet
does not recieve any parameters when I call config.getInitParameter().
Your help is very much appreciated.
- GIrish Wadhwani
# @(#)servlets.properties 1.86 97/11/14
#
# Servlets Properties
#
# servlet.<name>.code=class name (foo or foo.class)
# servlet.<name>.initArgs=comma-delimited list of {name, value} pairs
# that can be accessed by the servlet using the
# servlet API calls
#
# session servlet
servlet.session.code=SessionServlet
# simple servlet
servlet.simpleservlet.code=SimpleServlet
# snoop servlet
servlet.snoop.code=SnoopServlet
# survey servlet
servlet.survey.code=SurveyServlet
servlet.survey.initArgs=\
resultsDir=\tmp
#Mainservlet
servlet.main.code=MainServlet
servlet.main.initArgs=\
passwordFile=group.names\
sessionFile=group.session
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