Just asking... are you trying to connect your applet to machine other than
the machine from where your browser downloaded the applet ? If so, then
you'r trying to violate the so called "browser sandbox"... You can always
connect an unsigned applet to host from which you'v downloaded the applet.
Slavikos
################################################################
Filippos Slavik
Part of the SIAMS's implementation development team. For more
information, please check http://www.siams.net
e-mail : [EMAIL PROTECTED]
################################################################
"The software said 'runs on Win95 or better,' so I installed
it on Linux..."
----- Original Message -----
From: ANUPAMA PONNAPALLI <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, June 04, 1999 12:54 PM
Subject: Crazy Problem !! Please Help !!!! ! Please Help !!!! Urgent !!!
> Hi,
> I am facing a crazy problem and its driving me nuts... I
> have developed an applet, which calls servlets to get the data
> from db2. I have tested the applet in the appletviewer,
> and it works smoothly.
> The problems started once I started testing it in the
> browser (IE 4.0) . It still runs smoothly (in the browser), on
> my machine where the servletrunner is also running But
> when I test it on other PCs (IE 4.0 again), it throws an
> exception : InternetReadFile exception. I have not been
> able to find any explanation for it in the Java documentation.
> It throws this exception when I read the object being passed
> from the servlet. It gets the ObjectInputStream without any
> exception. the code is as below :
>
> public Vector executeQuery(String servlet, Vector send) {
> try
> {
> URL ptl = new URL(url + servlet);
> URLConnection c = ptl.openConnection();
>
> c.setDoOutput(true);
> c.setDoInput(true);
>
> ObjectOutputStream out = new
> ObjectOutputStream(c.getOutputStream());
> out.writeObject(send);
>
> ObjectInputStream in = new
> ObjectInputStream(c.getInputStream());
> rv = (Vector) in.readObject(); // exception here
>
> in.close();
> out.close();
> }catch (Exception e) {
> System.out.println("Exception: " + e);
> }
>
> if (rv == null) {
> JOptionPane.showMessageDialog(null, "Error in
> Mainframe access");
> System.out.println("error : rv is null");
> error = true;
> return null;
> }
> }
>
> In the servlet, I print the vector contents just before
> writeObject(reply), the data is properly displayed. here is the
> servlet code :
>
> try {
> ObjectInputStream in = new
> ObjectInputStream(req.getInputStream());
> input = (Vector) in.readObject();
> in.close();
> }catch (Exception e) {
> System.out.println("exception " + e);
> }
>
> // database access operations
>
> try {
> ObjectOutputStream out = new
> ObjectOutputStream(res.getOutputStream());
> System.out.println("reply = " + reply); // data seen
> correctly
> out.writeObject(reply);
> out.close();
> }catch (Exception e) {
> System.out.println("exception " + e);
> }
> }
> This behavior is unpredictable. Sometimes, the first call
> to the servlet goes off smoothly, it gives problems second or
> third call onwards. Its just driving us crazy... Please help us
> out with this problem.. any suggestions are welcome...
> Thanking you, in anticipation,
>
> Anupama
>
>
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>
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