Hi
We also faced the similar problem howver the foll entries in the autoexec.bat
solved our problem
set PATH=.;c:\JSDK;D:\jdk1.2\bin;c:\javawebserver1.1\jre\bin;
set
CLASSPATH=.;D:\jdk1.2\src.jar;c:\jsdk\jsdk2.1\server.jar;c:\jsdk\jsdk2.1\servlet.jar;
instead of server.jar and servlet.jar you could use jws.jar in your classpath
Hope this will help you.
Bye
Nitin
McKisson, Shawn wrote:
> There is a difference between PATH and CLASSPATH.
> What you want is for your CLASSPATH to point to the proper classfiles.
> Last time I downloaded the JSDK, is came as a jar file and was in the /lib
> directory.
> So what you need is (in a system independent pseudo-language)
>
> CLASSPATH = .../JSDK/lib/jsdk.jar
>
> --shawn
>
> -----Original Message-----
> From: Mark Phelps [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, July 25, 1999 8:20 AM
> To: [EMAIL PROTECTED]
> Subject: how to compile a servlet program
>
> I can successfully run sample servlets using Microsoft Personal Web
> Server with JRun, but have not yet succeeded in compiling one.
>
> I attempted to do so using JDK 1.1.5 with the JSDK servlet extension
> which I had downloaded.
> This didn't work, so I downloaded JDK 1.2.2 - but I still get the
> same problem - a) 'package javax.servlet not found in import' and
> 'package javax.servlet.http not found in import'; b) 'superclass
> HttpServlet of class Properties (the class I'm compiling) not found.'
>
> My path statement in autoexec.bat is set to c:\jdk1.2.2\bin. Is this
> where the javax classes are found ? This all looks different to me from
> JDK1.1.x, which used a CLASSES.ZIP file (the JDK1.2.2 documentation says
> this is not required). And where is the class HttpServlet ?
>
> --
> Mark Phelps
>
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