Hi!,
No, It wont work....
The result will be null . Method parameters variables are created
when a method is invoked and its value is initialized with the method
argument.
i.e copy of actual argument is passed not the actual argument.
Shiraz
-----Original Message-----
From: Chris Pratt <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Thursday, August 12, 1999 7:32 PM
Subject: Re: will this code work?
>Yes it will. But that is an awefully convoluted way of doing
>out.println("my name"); At this point I would suggest you read through the
>Java Tutorial on Sun's site, it's free and it will teach you these
>rudimentary things.
> (*Chris*)
>
>----- Original Message -----
>From: Duke Martin <[EMAIL PROTECTED]>
>To: <[EMAIL PROTECTED]>
>Sent: Thursday, August 12, 1999 4:57 PM
>Subject: will this code work?
>
>
>> String temp = null;
>> temp = process_me(temp);
>>
>> out.println(temp);
>>
>> public String process_me(String temp)
>> {
>> temp = "my name";
>> return temp;
>> }
>>
>> I would like to this the output of this servlet to print "my name" to the
>> screen. Will this work?
>>
>> thanks
>>
>>
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>
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