Hi, I am a newbie.Please help me how to make my Code Base File Applet to open an URL. My Applet runs in localdisk i.e., D:/JAVA/Client.html. When I run my applet to open an URL, I get 'Code Base files Cannot open https...'. My Applet just needs to invoke a servlet defined in http://localhost:8080/servlet/My2Servlet. I have been not able to solve this provlem since long time. Lot of work with RMI is also pending. What should I put in CodeBase field of Policy Entry? Should I put D:/JAVA/Client.html? What should I put for Permission, Target name and actions? (I am not using files). And also where should I put my Servlet URL. Please suggest good URLS to do this. I would be very happy if somebody can help me. Thank you. Venkata. ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
