How can I to make a connection to the server and retrieve the file if the
file I am trying to open is not in the same machine ?
>From: Andras Balogh <[EMAIL PROTECTED]>
>Reply-To: "A mailing list for discussion about Sun Microsystem's Java
> Servlet API Technology." <[EMAIL PROTECTED]>
>To: [EMAIL PROTECTED]
>Subject: Re: How to open a file using Web Address ?
>Date: Tue, 12 Oct 1999 09:14:34 +0200
>
>Hi,
>
>
> You have to use an absolute path to the file
>not an url.
> Maybe You are thinking that this way the servlet
>will be portable. Instead of your aproach you can
>have an init parameter that describes the full path minus the filename
>and i thing you can retrieve the init parameter with:
>
>String pathtofile=getServletConfig().getInitParameter("filepath");
>
> If the file you are trying to open is not in the same machine than
>you have to make a connection to the server and retrieve the file but i
>think this will be
>to slow for a servlet ( i mean the request from the client times out).
>
>
> ----- Original Message -----
> From: Hartono (Telebot)
> To: [EMAIL PROTECTED]
> Sent: Monday, October 11, 1999 3:29 PM
> Subject: How to open a file using Web Address ?
>
>
> Hi ...
>
> I want to open an HTML file using a servlet, so I didn't have to code
>the HTML in my servlet !
> Currently I'm using the path to my C: drive like the following lines !!
>
> FileObject endObj = new
>FileObject("C:\\servlet\\PostingJob\\end.html");
>
>
> But when I changed the referenced like :
>
> FileObject endObj = new
>FileObject("http://localhost:8000/servlet/PostingJob/main.html");
>
> The servlet cannot open the file and give me an exception ???
>
> any body know how to do this ??
>
> any help would very appreciated !!
>
> regards,
> Hartono sutirman
>
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