Another solution can be using intern() for your strings.
It follows that for any two strings s and t, s.intern() == t.intern() is
true if and only if s.equals(t) is true.
See more details in SDK doc,
Dmitry.
----- Original Message -----
From: "David Mossakowski" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, November 30, 1999 9:59 AM
Subject: Re: Comparing Strings
> In Java (unlike c++) the "==" operator compares *references* and not the
value.
> Therefore since the two strings are different objects they are !=.
>
> Java doesn't provide for operator overloading as c++ does so you're stuck
with
> using String.equals(String) call. Also how can you say that str1 and str2
point to
> the same object reference? They are not the same object.
>
> >From API:
>
> String str = "abc";
>
> is equivalent to:
>
> char data[] = {'a', 'b', 'c'};
> String str = new String(data);
>
>
> dave.
>
> fgs wrote:
>
> > Yes, Mr Craig,
> >
> > What we want is
> > when
> > str1="Hello"
> > str2="Hello"
> > points to the same object reference given by the documentation then
> > str1==str2 should return true
> > but it does not Why?
> > This is our question.............
> > FGS Infotech Private Limited
> >
> > ----- Original Message -----
> > From: Craig R. McClanahan <[EMAIL PROTECTED]>
> > To: fgs <[EMAIL PROTECTED]>
> > Cc: <[EMAIL PROTECTED]>
> > Sent: Tuesday, November 30, 1999 2:15 AM
> > Subject: Re: request.getParameter() in an if statement
> >
> > > fgs wrote:
> > >
> > > > nOT ONLY THAT WE ALSO have the same problem with
> > > >
> > > > Case 1:
> > > > String str="Hello";
> > > > String str2="Hello";
> > > >
> > > > Case 2:
> > > > String str=new String("Hello");
> > > > String str2=new String("Hello");
> > > >
> > > > Java Documentation says that in case 1, The JVM does not create an
> > object
> > > > for str2 but passes the same memory reference of str to str2. Only
in
> > the
> > > > second case it creates differednt objects for two variables.
> > > > If this is so , then for the first case str == str2 must return
true.
> > But
> > > > this does not happen? We get confused with this.
> > > >
> > > > But the statement str2.equals(str) will return true in both the
cases?
> > > >
> > > > Any Java Team member can answer this question?
> > > >
> > >
> > > Please see the API documentation for the equals() method, first for
> > > java.lang.Object and then for java.lang.String. It is up to a class
to
> > define for
> > > itself what one object being "equal to" another means. In the case of
> > strings, it
> > > means that the two strings represent the same sequence of characters.
In
> > both of
> > > the above cases, this test passes so they both return "true".
> > >
> > > For your own classes, you have the choice of overriding equals() to
test
> > what you
> > > want. If you do not override it, equals() defaults to the test
included
> > in
> > > java.lang.Object, which says two references are equal if they refer to
the
> > same
> > > exact object instance. For example:
> > >
> > > Given:
> > >
> > > MyClass obj1 = new MyClass(...);
> > > MyClass obj2 = new MyClass(...);
> > > MyClass obj3 = obj1;
> > >
> > > Then:
> > >
> > > (obj1 == obj2) returns false -- they are different instances.
> > > (obj1 == obj3) returns true -- they are the same instance.
> > >
> > > Using an equals() test would return the same results if you do not
> > override it.
> > >
> > > >
> > > > -FGS Infotech Private Limited......
> > > >
> > >
> > > Craig McClanahan
> > >
> > >
> > >
> >
> >
===========================================================================
> > To unsubscribe: mailto [EMAIL PROTECTED] with body: "signoff
JSP-INTEREST".
> > FAQs on JSP can be found at:
> > http://java.sun.com/products/jsp/faq.html
> > http://www.esperanto.org.nz/jsp/jspfaq.html
>
> --
> David Mossakowski [EMAIL PROTECTED]
> Programmer 212.310.7275
> Instinet Corporation
>
> "I don't sit idly by, I'm planning a big surprise"
>
>
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