Richard...
Richard Clark wrote:
> Look at my code again...
>
> if (null == s || s.length() == 0) ...
>
> Java translates x == y into x.equals(y). If I had said
> if (s == null)
> and s was null, you would get a null pointer exception.
What? Which version of Java "translates x == y into x.equals(y)"? I have
never heard of this, and it troubles me greatly as I've written code
that relies on the differences between == and equals().
More on topic: I tend to us the following:
if ( "someValue".equals( s ) ) {}
Unless I need to check specifically for a null value, in which case I
use:
if ( s != null && s.length() > 0 ) {}
- Paul Philion
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