Go to the directory from which you can see the directory package1. Add this
directory to your classpath.
--dhina
-----Original Message-----
From: Nic Ferrier <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Tuesday, January 11, 2000 1:46 PM
Subject: Re: Compile Error when referring to other servlets in the same
package ??
>>>> "Leung, King Sang Eric" <[EMAIL PROTECTED]> 11-Jan-00
>7:03:34 AM >>>
>
>
>>I have in my windows directory 2 .java servlets in the
>>same package1.
>>Ie. ..\servlet\package1\a.java
>> ..\servlet\package1\b.java
>
>>c:> javac b.java - ERRORS a.function_a is a invalid name, class
>variable...
> ^
>>CLASSPATH=.c:\jsk1.2.2\jre\lib\rt.jar;c:\jswdk-1.0.1\lib\servlet.jar;c:\
>>jswdk-1.0.1\lib\jspengine.jar;c:\jswdk-1.0.1\webpages\WEB-INF\servlets
>
>>Anyone kindly tells me what is wrong? Is it in the program
>>declaration, or in the environment setting or else?
>
>The compiler must be able to find the class that you refer to and it
>can't.
>
>Most likely this is because the CLASSPATH does not include the
>directory where the .class files are being compiled to.
>
>Something like this would probably do the trick:
>
>c:\> javac -d c:\destinationdir a.java b.java
>
>Note that it is possible to compile both at once.
>
>
>This is one of the fundamental errors with servlets, compiling
>classes to the wrong directory. You will also have to have them in a
>particular dir to get them to work as servlets.
>
>
>
>Nic Ferrier
>
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