One potential problem with that approach is that you can't benefit from servlet
reloading: if you need it the jar file should be included in the repositories
line for the zone, rather than the wrapper.classpath line in jserv.properties.
- simon
Noel E Lecaros wrote:
> I don't know the specifics of your setup but mine looks like this:
>
> Apache+mod_jserv using JDK 1.2.2 on Linux
> a jar file named myservlets.jar in the directory /opt/apache/servlets
> a servlet in the jar file named com.sample.LoginServlet.class
> the servlet's alias is "login"
> the web server's name is "www.webserver.com"
>
> 1. in the HTML, write:
> ACTION="http:/www.webserver.com/servlets/login"
> 2. in the zone.properties file for the servlet's zone, write:
> servlet.login.code=com.sample.LoginServlet
> 3. in the jserv.properties file, add the line:
> wrapper.classpath=/opt/apache/servlets/myservlets.jar
> right after the other "wrapper.classpath" entries. This is the
> CLASSPATH that the servlet engine actually uses.
>
> Your setup may vary, but it shouldn't be too difficult to extrapolate from
> here.
>
> Punam Chordia <[EMAIL PROTECTED]> on 03/09/2000 06:37:52 PM
>
> Please respond to "A mailing list for discussion about Sun Microsystem's
> Java Servlet API Technology."
> <[EMAIL PROTECTED]>
>
> To: [EMAIL PROTECTED]
> cc:
> Subject: putting servlets in a jar
>
> Hi friends,
> On out client's webserver(apache+JServ1.0) there are many web applications
> running.
> We have around 10-15 servlets which we require to put in a jar file.
> Our frontend is HTML/Javascript.
> How to call a servlet in a jar from the html page?
> I tried
> action = "<jar name>.<servlet name>"
> and also put the servlet in class path, but it didnt work.
> Some one who has done it, could u please give me the detailed information.
>
> Thanks in advance,
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