I am using a servlet that basically calls a db and returns some info. When
called initially with one query, it works fine, but if I change the query, I get
the following error. Any ideas what could be causeing it. I am stumped.
I am running Apache 1.3.12 w/ ApacheJserv, the latest version as of last
Thursday.
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On the web page, I get this error:
Internal Server Error
The server encountered an internal error or misconfiguration and was
unable to complete your request.
Please contact the server administrator, root and inform them of the
time the error occurred, and anything you might have done that may have
caused the error.
More information about this error may be available in the server error
log.
Apache/1.3.12 Server at www.stsbiz.net Port 80
_______________________________________________________________
The website.error.log:
[Tue Apr 25 12:27:24 2000] [error] [client <ipAddr>] Premature end of
script headers: /servlet/Report
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website.access.log
<Accessing machine> - - [25/Apr/2000:12:27:24 -0500] "POST
/servlet/Report HTTP/1.0" 500 583
_______________________________________________________________
mod_jserv.log:
[25/04/2000 12:27:24:683] (INFO) wrapper: Java VM not responding
(PID=30847) [timeout]
[25/04/2000 12:27:24:686] (EMERGENCY) ajp12[1]: cannot scan servlet
headers (500)
[25/04/2000 12:27:24:686] (ERROR) an error returned handling request via
protocol "ajpv12"
[25/04/2000 12:27:25:693] (EMERGENCY) ajp12: ping: no reply
(-1) Please make sure that the wrapper.classpath is
pointing to the correct version of ApacheJServ.jar
[25/04/2000 12:27:25:693] (INFO) wrapper: Java VM restarting (PID=30847)
[25/04/2000 12:27:25:694] (INFO) wrapper: Java VM spawned (PID=31014,
PPID=30847)
_______________________________________________________________
--
Thanks,
Larry M. Lemons
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