Hi Everyone,

I have written a wrapper class around Sun's XML parser to read a XML
file. I am using this class in my JSP and Servlets to parse the file and
read the contents. This set up is working fine in my development
environment of Sun's Java Web Server Development Kit. I have the file in
the server root directory.

I have taking a hosting service and deployed the jsp's and servlets. I
am having trouble reading that file though the jsp and servlets. Now, my
jsp and servlets are not able to locate the file. I tried using URL path
like http://hostname.com/filename.xml, to read the file also (the
XMLparser provides a method to provide the URL for the file path). But
still it is not able to locate it. I can access the file with a regular
java application using the same class through URL path.

My question is: How do I found out what path name should I provide for
the filename?

Thanks,
Sanjesh

___________________________________________________________________________
To unsubscribe, send email to [EMAIL PROTECTED] and include in the body
of the message "signoff SERVLET-INTEREST".

Archives: http://archives.java.sun.com/archives/servlet-interest.html
Resources: http://java.sun.com/products/servlet/external-resources.html
LISTSERV Help: http://www.lsoft.com/manuals/user/user.html

Reply via email to