using the following:
String url = http://blah.com/runme?a=b + URLEncoder.encode("&") + "c=7".
or you use the escape string for "&"
liwen
----- Original Message -----
From: "Mike Haberman" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, May 13, 2000 10:19 PM
Subject: Re: How can I get parameters with '&' in it ?
> String url = "http://blah.com/runme?a=b&c=7";
> response.encodeUrl(url) doesn't change the input.
>
> any ideas?
>
> thanks again!
>
> mike
>
> by the way I'm running ApacheJServ/1.1 on a freebsd box
>
>
>
>
> On Fri, May 12, 2000 at 10:14:04PM -0500, Chris Murphy wrote:
> > You need to encode the value of the url parameter.
> >
> > Look at the javax.servlet.http.HttpServletResponse.encodeURL(String url)
> > method.
> >
> > NOTE: you only want to encode the values, not the names, of the
parameters.
> > And it's
> > good practice to always do this.
> >
> > Good luck.
> >
> > -----Original Message-----
> > From: Mike Haberman [mailto:[EMAIL PROTECTED]]
> > Sent: Friday, May 12, 2000 8:11 PM
> > To: [EMAIL PROTECTED]
> > Subject: How can I get parameters with '&' in it ?
> >
> >
> > Hello all,
> >
> > I have a servlet that reads in parameters from a get request. The
> > problem is that one of the parameters is a url. If that url
> > has an '&' in it, then the parameters are split around it.
> >
> > for example:
> >
> > <A HREF =
"mysevlet?name=bob&age=23&url=http://blah.com/runme?a=b&c=7">
> >
> > in myservlet i get
> > name:bob
> > age:23
> > url:http:..runme?
> > a:b
> > c:7
> >
> > What's the fix so I only get three parameters?
> >
> > thanks for your time!
> >
> > [EMAIL PROTECTED]
> >
> >
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