>>> Geeta Ramani <[EMAIL PROTECTED]> 18-Jul-00 8:42:19 PM >>> >Ah, I think Harjit is right: you have to carry querystring >variables around.. No... you simply call: response.encodeURL(str); and that will do everything for you. The API specifies that the session id is in the form of a request argument. These are not the same as parameters, an encoded URL might look like this: http://someserver:8000/myservlet/;jsessionid=SOMEID But really you could find any of this out by looking it up - it's not really on to ask questions like this on the list. Nic Ferrier ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
