Hi Fellows, Will you please help me. Once I have made a servlet (.class) file. Now how could I check the output of my servlet? Although, I have downloaded and Unzipped the "Zip" File for running the JSDK2.1. But when I type C:\JSDK> startserver A Window Blink and I got the same prompt i.e. "C:\JSDK>". Then I start the Internet Explorer. AND I type http://localhost:8080/servlet/HTTPGetServlet in the Browser Address Window. I get message "Connecting to site 127.0.0.1" at the base line of Browser AND Then I get message in Browser output Window "The Page Cannot Be Displayed" Will you please advise me that where the Browser looks for the Servlet File? Is it a path error? What is the function of this directory structure "C:\jsdk\webpages\WEB-INF\Servlets" ? The properties of my "Default.cfg" file are as follow; server.port=8080 server.hostname=localhost server.inet= (What is this used for?) server.docbase=webpages\WEB-INF\Servlets server.tempdir=tmp server.webpages.WEB-INF.Servlets=examples (What is the function of it) server.webpages.WEB-INF.Servlets=examples (What is the function of it) Thanking you good guys in advance. Just a Novice Gill ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
