At 01:47 PM 9/28/00 +0530, you wrote:
>Hi friends,
>
>Already I had posted a doubt regarding how to run a servlet program
>
>The reply was to add a class path or the jar file and the jdk classes.zip
>
>I tried running with
>
>javac -classpath c:\jsdk2.0\lib\jsdk.jar;c:\jdk1.1.8\lib\classes.zip
>SimpleServlet.java
>
>and the servlet was compiled and i got the corresponding class file
>Question:
>Do i have to use this command every time i compile a servlet
>Can't i declare the class path somewhere else
>I have tried typing
> classpath c:\jsdk2.0\lib\jsdk.jar;c:\jdk1.1.8\lib\classes.zip in the
> autoexec.bat
>Please do give the exact solution
>
>Thanx in advance
>
>
>--
> V.T.R. Ravi Kumar
>
> Office : Resd.:
>--------- -------
> Information & Technology Department # Room No.68, ET Hostel - 2, Sector1
> Bharat Heavy electricals Limited # Bharat Heavy Electricals Limited
> Ranipur, Hardwar - 249 403, INDIA # Ranipur, Hardwar - 249 403, INDIA.
>
>___________________________________________________________________________
>To unsubscribe, send email to [EMAIL PROTECTED] and include in the body
>of the message "signoff SERVLET-INTEREST".
>
>Archives: http://archives.java.sun.com/archives/servlet-interest.html
>Resources: http://java.sun.com/products/servlet/external-resources.html
>LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
try the following
set CLASSPATH=c:\jsdk2.0\lib\jsdk.jar;c:\jdk1.1.8\lib\classes.zip
in the autoexec.bat on windows systems; This will work for apps running under
DOS windows.
Hackmann
___________________________________________________________________________
To unsubscribe, send email to [EMAIL PROTECTED] and include in the body
of the message "signoff SERVLET-INTEREST".
Archives: http://archives.java.sun.com/archives/servlet-interest.html
Resources: http://java.sun.com/products/servlet/external-resources.html
LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
