Slightly off topic

I think you problem is that you are not matching the data types correctly..

You need to form the SQL string differently ... you still have to keep
single speech marks as you are matching a string and compile the String with
the variable like below ..

String query="select * from userdet where uname = '" + username  + "' ";

That you should work ...

James


The datatype in the access tabl
----- Original Message -----
From: "s saravanan" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, November 16, 2000 12:10 PM
Subject: Retriving datas using odbc-jdbc connection in servlets


> Hi All!
>
>       I'am learning servlets now for my project. I have some doubts
> regarding the program which i have written:
>
> Here is my program....
> *********************
>
> import java.sql.*;
> import java.io.*;
> import java.util.*;
> import javax.servlet.*;
> import javax.servlet.http.*;
>
> public class testing extends HttpServlet
> {
>
>   public void doPost(HttpServletRequest request, HttpServletResponse
> response)throws
ServletException, IOException
>
>   {
>
>     PrintWriter out=response.getWriter();
>
>     try
>    {
>     Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
>     Connection con=DriverManager.getConnection("jdbc:odbc:test");
>
>     String username=request.getParameter("un");
>
>     Statement stmt=con.createStatement();
>     String query="select * from userdet where uname = username ";
>     ResultSet rs = stmt.executeQuery(query);
>
>   while(rs.next())
>   {
>    out.println(rs.getString(1));
>    }
>
>
>    out.close();
>    }
>    catch(Exception e)
>    {
>     out.println(e);
>    }
>   }
> }
>
>
> ****
>    Here 'test' is the DSN name. I'am using MS-Access as the database. I
want
> get the first column value in the userdet table by using the uname in the
> where condition.
>
>   Actually i'am getting the value in the variable username. That variable
i
> equated with the uname in the table. But it shows error saying:
>
> java.sql.SQLException: [Microsoft][ODBC Microsoft Access Driver] Too few
> parameters. Expected 1.
>
>
> If i give like:
>     select * from userdet where uname = 'ssarav';
>
>    ssarav is the real value in the table. Then it works.
>
> Even if i give like: select * from userdet; This  also works.
> But if i give variable name with the equated symbol , it does not work
> saying the above error.
>
> Please help me what to do....
>
> Bye,
> s.saravanan,
> web programmer,
> Alpha Systems,
> email-id: [EMAIL PROTECTED]
>
>
>
>
>
>
>
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