Enrique
Thanks for that , it worked....
Is there something similar you can do for the upload. I am using the
MultipartParser by Oreilly to do the upload, again i am having to create the
file on my server before I can save it as binary data to the database.
thanking you in advance
Parag
Enrique Ortiz Torrent <[EMAIL PROTECTED]> on 10/04/2001
11:53:55
Please respond to "A mailing list for discussion about Sun Microsystem's Java
Servlet API Technology." <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
cc: (bcc: Parag Patwa/LON/WLB)
Subject: Re: Displaying Images Dynamically using servlets
Hi
we develop a servlet in order to send directly the image to the browser,
here is the code :
public void doGet(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException
{
ServletOutputStream html_out;
java.lang.String query = SELECT IMAGE FROM DATABASE WHERE
IMAGENUMBER = " //replace with your select
Connection OraConn = conn.getConnection();
Statement stmt = OraConn.createStatement();
// select image from database
ResultSet Result = stmt.executeQuery(query+" "+files);
if (Result.next())
{
res.setContentType("image/jpeg");
byte[] bytes = Result.getBytes(1);
html_out = res.getOutputStream();
html_out.write(bytes);
}
}
if you want to use less memory, send in 4k blocks
Statement stmt = conn.createStatement();
// select image from database
ResultSet Result = stmt.executeQuery(query+" "+files);
ServletOutputStream out = res.getOutputStream();
while (Result.next())
{
res.setContentType("image/jpeg");
BufferedInputStream gifData = new
BufferedInputStream(Result.getBinaryStream(1));
byte[] buf = new byte[4 * 1024]; // 4K buffer
int len;
while ((len = gifData.read(buf, 0, buf.length)) != -1)
out.write(buf, 0, len);
}
bye
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