> Sourabh Kulkarni wrote:
>
> I am trying to send an object to servlet.
> URL url = new URL("http://localhost:8080/context/servletname?param=value";);
> 2] If i use request.getParameter("param") and then go ahead with reading
> the object, I get the following excetpion on server.
>
> at javax.servlet.http.HttpUtils.parseQueryString(HttpUtils.java:151)
> at javax.servlet.http.HttpUtils.parsePostData(HttpUtils.java:254)
> at org.apache.tomcat.util.RequestUtil.readFormData(RequestUtil.java:101)
> at org.apache.tomcat.core.RequestImpl.handleParameters(RequestImpl.java:691)
> at org.apache.tomcat.core.RequestImpl.getParameterValues(RequestImpl.java:259)
> at org.apache.tomcat.core.RequestImpl.getParameter(RequestImpl.java:250)
>
The servlet container is trying to read your POST'ed object
as a form. That should only happen if your content-type is
"application/x-www-form-urlencoded", which is (always?) the
default if you don't set it to anything else.
Are you setting the Content-Type?
--
Christopher St. John [EMAIL PROTECTED]
DistribuTopia http://www.distributopia.com
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