Hugo,
Can you describe what your applet is doing again?  It still sounds like it
is trying to make a HttpURLConnection to a server that is different from
where the applet was downloaded from.  Doing this is a security exception
and changing the permissions is not going to help.

-Richard


At 06:54 PM 9/20/01 +0100, you wrote:
>You were right, about the name server. The problem was that i was using an
>older version of my file where i've already have changed the name of the
>server.
>
>However the problem persists in another way. In localhost it gives no error
>but when i run my application in another computer it gives me now another
>error.
>
>Exception occurred during event dispatching:
>java.security.AccessControlException: access denied
>(java.net.SocketPermission phc:8000 connect,resolve)
>at java.security.AccessControlContext.checkPermission(Unknown Source)
>at java.security.AccessController.checkPermission(Unknown Source)
>at java.lang.SecurityManager.checkPermission(Unknown Source)
>at java.lang.SecurityManager.checkConnect(Unknown Source)
>at sun.plugin.protocol.jdk12.http.HttpURLConnection.connectStep1(Unknown
>Source)
>at sun.plugin.protocol.jdk12.http.HttpURLConnection.connect(Unknown Source)
>at Veiculos_Panel.getFromServlet(Veiculos_Panel.java:712)
>at Veiculos_Panel.procuraButtonActionPerformed(Veiculos_Panel.java:615)
>at Veiculos_Panel$5.actionPerformed(Veiculos_Panel.java:426)
>at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
>at javax.swing.AbstractButton$ForwardActionEvents.actionPerformed(Unknown
>Source)
>         at javax.swing.DefaultButtonModel.fireActionPerformed(Unknown Source)
>         at javax.swing.DefaultButtonModel.setPressed(Unknown Source)
>at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(Unknown Source)
>at java.awt.Component.processMouseEvent(Unknown Source)
>at java.awt.Component.processEvent(Unknown Source)
>at java.awt.Container.processEvent(Unknown Source)
>at java.awt.Component.dispatchEventImpl(Unknown Source)
>at java.awt.Container.dispatchEventImpl(Unknown Source)
>at java.awt.Component.dispatchEvent(Unknown Source)
>at java.awt.LightweightDispatcher.retargetMouseEvent(Unknown Source)
>at java.awt.LightweightDispatcher.processMouseEvent(Unknown Source)
>at java.awt.LightweightDispatcher.dispatchEvent(Unknown Source)
>at java.awt.Container.dispatchEventImpl(Unknown Source)
>at java.awt.Component.dispatchEvent(Unknown Source)
>         at java.awt.EventQueue.dispatchEvent(Unknown Source)
>at java.awt.EventDispatchThread.pumpOneEventForHierarchy(Unknown Source)
>at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
>         at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
>         at java.awt.EventDispatchThread.run(Unknown Source)
>
>
>And my java.policy file looks like this:
>
>grant {
>permission java.security.AllPermission;
>};
>
>Thanks for your help.
>
>Hugo Malheiro
>
>
>-----Original Message-----
>From: A mailing list for discussion about Sun Microsystem's Java Servlet
>API Technology. [mailto:[EMAIL PROTECTED]]On Behalf Of
>Sohaila Roberts
>Sent: quinta-feira, 20 de Setembro de 2001 15:10
>To: [EMAIL PROTECTED]
>Subject: Re: java.net.ConnectException in applet connection to servlet
>
>
>try putting the actual server's name that the servlet is running on,
>instead of localhost
>
> >                         URL url = new
>URL("http://localhost:8000/main?"+URLEncoder.encode("opcao")+
> >
>"="+URLEncoder.encode(opcao)+"&"+URLEncoder.encode("param")+
> >
>"="+URLEncoder.encode(param));
> >                 URLConnection con = url.openConnection();
> >                 con.setDoOutput( true );
> >         con.setDoInput( true );
> >         con.setUseCaches( false );
> >         con.setDefaultUseCaches(false);
> >                 InputStream in = con.getInputStream();
> >                 ObjectInputStream objStream;
> >                 objStream = new ObjectInputStream(in);
> >                 obj = (Object)objStream.readObject();
> >                 objStream.close();
> >                 in.close();
> >
> >                 }catch(IOException o){o.printStackTrace();}
> >                 catch(ClassNotFoundException c){c.printStackTrace();}
> >
> >
> >                 return obj;
> >         }
> >
> > (I return an object some that i can use the same function in diferent
> > places)
> >
> > I've looked in the archives and in search engines for this exception, but
>i
> > did not find anything relevant. Some if anyone can help me i would
>apreciate
> > it.
> >
> > Thanks for you time.
> >                                                 Hugo Malheiro
> >
> >
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