Thanks for your response,
But the reason should be something different. You are true, accept is
blocking waiter.
If I put it into while loop, my application hosts more than one connection.
On the otherhand one connection is enough for my application.
Problem is that: application couldn't aware connection request if I try to
connect in servlet.There could be different reasons, I'll search.
Regards,
Fusun
----- Original Message -----
From: "Richard Yee" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, September 24, 2001 9:15 AM
Subject: Re: Socket connection is servlet
> Fusun,
> The application should always be listening for connections.
> Your serverSocket.accept() method call should be in a while loop like
this:
>
> // server infinite loop
> import java.net.*;
> import java.io.*;
>
> public class tcpServer {
>
> public static void main(String args[]) {
>
> int port;
> ServerSocket server_socket;
> BufferedReader input;
>
> try {
> port = Integer.parseInt(args[0]);
> }
> catch (Exception e) {
> System.out.println("port = 1500 (default)");
> port = 1500;
> }
>
> try {
>
> server_socket = new ServerSocket(port);
> System.out.println("Server waiting for client on port " +
> server_socket.getLocalPort());
>
> while(true) {
> Socket socket = server_socket.accept();
> System.out.println("New connection accepted " +
> socket.getInetAddress() +
> ":" + socket.getPort());
> input = new BufferedReader(new
> InputStreamReader(socket.getInputStream()));
> // print received data
> try {
> while(true) {
> String message = input.readLine();
> if (message==null) break;
> System.out.println(message);
> }
> }
> catch (IOException e) {
> System.out.println(e);
> }
>
> // connection closed by client
> try {
> socket.close();
> System.out.println("Connection closed by client");
> }
> catch (IOException e) {
> System.out.println(e);
> }
>
> }
>
> The accept method will block until a connection is made to the server
> socket port. Once a socket is established, you need to do whatever you
> need to do to process the data going into or out of the socket by getting
> the input or output streams of the socket and reading or writing from it.
>
> To read more about socket programming, go to: http://pont.net/socket/java/
>
> -Richard
>
> At 08:30 AM 9/24/01 +0300, you wrote:
> > Assume that an application waits for connection :
> > ServerSocket s = new ServerSocket(8088);
> > Socket clientSocket = serverSocket.accept();
> >
> > A Servlet want to make connection:
> > PrintWriter pw = response.getWriter();
> > Socket clientSocket = new Socket(hostAddress, 8088);
> > pw.println("<HTML>");
> > pw.println("<BODY>");
> > pw.println("hello!");
> > pw.println("</BODY>");
> > pw.println("</HTML>");
> >
> >
> >
> > Nothing more is in doGet or doPost method.
> >
> > I call servlet from browser, servlet prints hello and stops.
However,
> >application still waiting connection.
> >
> > Thanks,
> >
> >
> >
> >
> >
> >
> >----- Original Message -----
> >From: "Christopher K. St. John" <[EMAIL PROTECTED]>
> >To: <[EMAIL PROTECTED]>
> >Sent: Friday, September 21, 2001 9:11 PM
> >Subject: Re: Socket connection is servlet
> >
> >
> > > Fusun CITAK wrote:
> > > >
> > > > I must connect with this application from a servlet.
> > > > Is that possible?
> > > >
> > >
> > > Yes.
> > >
> > >
> > > > What is wrong?
> > > >
> > >
> > > Without details, it's a little hard to tell. If
> > > you can't post your code, at least post any error
> > > messages you're getting. Or something.
> > >
> > >
> > >
> > > --
> > > Christopher St. John [EMAIL PROTECTED]
> > > DistribuTopia http://www.distributopia.com
> > >
> > >
>
>___________________________________________________________________________
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> >body
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> > >
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> > > Resources:
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> > >
> >
>
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>
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