I had a similar problem and managed to solve it by getting the system
properties.
Properties prop = System.getProperties();
Enumeration eKeys = prop.getKeys();
Enumeration eElements = prop.getElements();
while(eKeys.hasMoreElements()) {
System.out.println("key = " + eKeys.nextElement();
System.out.println("property" = " + eElements.nextElement();
}
I was then able to find the user.dir property.
This property is where the Java VM sets it default path to be.
For myself this was the system32 directory under winnt.
I then placed the file in there and it picked it up ok.
Hope this helps
David Gibson
___________________________________________________________________________
To unsubscribe, send email to [EMAIL PROTECTED] and include in the body
of the message "signoff SERVLET-INTEREST".
Archives: http://archives.java.sun.com/archives/servlet-interest.html
Resources: http://java.sun.com/products/servlet/external-resources.html
LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
