You can use this for example
java.io.BufferedReader in =
new java.io.BufferedReader(new
java.io.FileReader("c:\\odd_directory\\web\\templates\\page.html"));
do {
Riga = in.readLine();
if (Riga == null) {
in.close();
break;
}
ContenutoFile = ContenutoFile + Riga +
"\n";
} while (true);
Hope that it can be help you.
Regards
Rinaldo
[EMAIL PROTECTED]
-----Messaggio originale-----
Da: A mailing list for discussion about Sun Microsystem's Java Servlet
API Technology. [mailto:[EMAIL PROTECTED]] Per conto di
wilbert moore
Inviato: gioved� 7 marzo 2002 21.22
A: [EMAIL PROTECTED]
Oggetto:
What I'm trying to do is probably pretty simple.
Its pretty easy to do in VB/ASP so I know this
will be a breeze for someone to answer.
My servlet is to read in an html file's contents which is sitting in a
folder under the main server's root. Since I have not yet been
successful in configuring tomcat to work under apache's control, my
servlet is at http://localhost:8080/servletname
If my html file is at http://localhost:80/page.html, what is the call I
need to make to find the raw directory (eg.
c:\odd_directory\web\templates\ )
I could obviously code this in hard, which I did to test so far,
however, if the app were moved, this would not work.
Thanks for the help, and I hope I supplied enough info for this simple
task.
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