I guess u r issue can easily solved by instead u use JSP.. and ask the
Form to submit the information to the same jsp itself.


Hope the following code helps..
Name this file as simple.jsp

<%@ page import="java.sql.*, java.io.*" %>

<html>
<body >
<form action="http://localhost/samples/simple.jsp " method="post">
<input type="text" name="T1" size="31">
<%
        String reqParam=request.getParameter("parameterName ");
        if reqParam=="some value"
        {
        out.println("  some thing ");
        }
        else{
         out.println(" some other thing ");
        }

%>
<input type="submit" value="Submit" name="B1">
</form >
</body>
</html >


Sorry if this solution is off the track  :(
Aroon


-----Original Message-----
From: A mailing list for discussion about Sun Microsystem's Java Servlet
API Technology. [mailto:[EMAIL PROTECTED]] On Behalf Of
Gehan G.
Sent: Thursday, May 16, 2002 8:49 AM
To: [EMAIL PROTECTED]
Subject: Re: HTML read question


Sorry for not being clear...
 My intentions are to read the current webpage that the button resides
on. For instance I have a web page with a button at the bottom, when a
user clicks that button I want the servlet to read that page(including
the button) and then append something to the end... then output the
page(with new info)...  I think I can get the bufferedReader to work..
I'll let you know if there is any problems. Thanks for your reply...

gehan Gehale

--- Mike Whittaker <[EMAIL PROTECTED]> wrote:
> Do you mean a web page you have access to ie on your server or some
> other web page.
> If the former read it in from a BufferedReader
> If the latter you will need to make a URLConnection and read
> it in that way
> eg:
>
>                         InputStream is;
>                         URLConnection uc;
>                         StringBuffer sourceBuffer = new
> StringBuffer();
>                         try{
>                                 URL userUrl = new URL(myURL);
>                                 uc = userUrl.openConnection();
>                                 is = userUrl.openStream();
>                                 BufferedReader in = new
> BufferedReader(new InputStreamReader(is));
>                                 String line = null;
>                                 while((line = in.readLine()) != null)
> {
>
> sourceBuffer.append(line);
>                                 }
>                                 is.close();
>                         }
>                         catch(Exception e) {}
>
> You're not being very clear in your intention.
>
> Mike W.
>


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