this results in a
cannot forward after response has been committed
error in the Tomcat System.out. window.
Note: I am having my accountServlet call a
GroupServlet
Rich
-- Gayathri Palicherla <[EMAIL PROTECTED]>
wrote:
> Replace application with getServletContext()i.e
>
(getServletContext()).getRequestDispatcher("/to/your/URL").forward(request,response);
>
> This should work for you.
>
> -- Gayathri.
>
>
> Rich:
>
> Just an idea:
> remove the offending line from your jsp. then
> compile it. Look a the servlet
> which your jsp generates (usually in a "work"
> dirctory) and then search for the
> word "application". (You probably won't find it.)
>
> I found "ServletContext application = null;"
> decalred in the" _jspService"
> method of one of my jsps. What do you have? If you
> have something else, you
> could substitute that name for "application".
>
> Regards,
> Geeta
>
> Richard Diaz wrote:
>
> > I'm using tomcat 4.0 on apache
> > 1.3.20 on windows 98.
> >
> > Well i was losing all my session variables and
> FINALLY
> > found this article:
> >
> > http://www.jguru.com/faq/view.jsp?EID=816599
> >
> > so i changed all my response.sendRedirect()
> methods to
> >
> > response.encodeRedirectURL()
> >
> > but those failed to actually move forward so i
> changed
> > them all to:
> >
> >
>
application.getRequestDispatcher("/to/your/URL").forward(request,response);
> >
> > and now I get a compile error "cannot resolve
> symbol.
> > symbol: application
> >
> > do i have to include the 'application' somehow?
>
>
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