Don't encode the full URL just the values of the parameters. d.
Hiren Dossani wrote:
hello, i am receiving url as the request parameter. the url for example is, "http://www.google.com/search?hl=en&ie=UTF-8&oe=UTF-8&q=servlet"; i want to use response.sendRedirect() method to rdirect to the url page. i tried String urlStringFromRequest = URLEncoder.encode(request.getParameter("url")); and then use, response.sendRedirect(urlStringFromRequest) but this fails as the urlStringFromRequest value is read as: http%3A%2F%2Fwww.google.com%2Fsearch%3Fhl%3Den thanks for your help. -- hiren ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
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