If you use authentication with a 401 type access, ( user/log on box prompted by the browser ), I doubt you can bypass it by setting >something in the headers, it may be possible, but I don't see how. If someone knows better, please correct me. I've had this situation before.
I've did it. you just have to copy the key=value pair in the headers and the authentication is done. In case of a basic authentication here is how to do it.
String authorization = request.getHeader("authorization"); URL priv = new URL(...); URLConnection uc = priv.openConnection(); uc.setRequestProperty ("authorization", authorization); Marc. _________________________________________________________________ STOP MORE SPAM with the new MSN 8 and get 2 months FREE* http://join.msn.com/?page=features/junkmail ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html