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resultset.next(); is missing
Vj
----- Original Message -----
Sent: Thursday,March 13,2003 9:23
AM
Subject: Exception on Result Sets
Hi all,
I'm developing a SERVELT for a WebPage and when I try to get a String of a
ResultSet, occurs the following exception:
Java.SQL.SQLException : Before start of Result Set
This is the code's part with bug:
try {
Class.forName("org.gjt.mm.mysql.Driver").newInstance();
conexao =
DriverManager.getConnection("jdbc:mysql://localhost/Database?user=root&password=");
st1 = conexao.createStatement(); st2 =
conexao.createStatement(); st3 =
conexao.createStatement(); IDTemp =
request.getParameter("id");
IDTC=Integer.parseInt(IDTemp); ResultSet rs
= st1.executeQuery("SELECT * FROM classifgeral WHERE IDTC="+
IDTC); ResultSet rs2 =
st2.executeQuery("SELECT * FROM tipo_classificado WHERE IDTC="+
IDTC);
IDVS=rs.getInt("idvs"); ResultSet
rs3=st3.executeQuery("SELECT * FROM cad_visitan tes WHERE id ="+
IDVS);
tipClass=rs2.getString("TIPO");
descClass=rs2.getString("DESCRICAO");
Somebody has a idea?
Regards,
Rafael Chiarinelli
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