resultset.next(); is missing
 
Vj
----- Original Message -----
Sent: Thursday,March 13,2003 9:23 AM
Subject: Exception on Result Sets

Hi all,

I'm developing a SERVELT for a WebPage and when I try to get a String of a ResultSet, occurs the following exception:

Java.SQL.SQLException : Before start of Result Set

This is the code's part with bug:

    try {
      Class.forName("org.gjt.mm.mysql.Driver").newInstance();
      conexao = DriverManager.getConnection("jdbc:mysql://localhost/Database?user=root&password=");
  
      st1 = conexao.createStatement();
      st2 = conexao.createStatement();
      st3 = conexao.createStatement();
      IDTemp  = request.getParameter("id");
      IDTC=Integer.parseInt(IDTemp);
      ResultSet rs = st1.executeQuery("SELECT * FROM classifgeral WHERE IDTC="+ IDTC);
      ResultSet rs2 = st2.executeQuery("SELECT * FROM tipo_classificado WHERE IDTC="+ IDTC);
      IDVS=rs.getInt("idvs");
      ResultSet rs3=st3.executeQuery("SELECT * FROM cad_visitan tes WHERE id ="+ IDVS);
      tipClass=rs2.getString("TIPO");
   descClass=rs2.getString("DESCRICAO");

Somebody has a idea?

Regards,

Rafael Chiarinelli



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