> see skip-out logic in expression evaluation

a friend just whacked me for being obscure by using compiler and
language geekery.  sorry.

when evaluating

   A & B, if A is false, there is no sense evaluating B.

   A | B, if A is true, there is no sense evaluating B.

this sometimes surprises new programmers when B is, for example, a
function with side effects.

randy

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