as you just said Thats a very tricky subject!
I refer to this article "Clas Persson et all, Phys Rev B 72, 035211 (2005)"
to define VBM , it explains in detail many things. thank you again
 
slimane,
 

--- En date de : Lun 7.2.11, N H <[email protected]> a écrit :


De: N H <[email protected]>
Objet: Re: [SIESTA-L] semi metalic caracter
À: [email protected]
Date: Lundi 7 février 2011, 13h22


Hy Slimane


You can perform the calculation by changing one parameter in the fdf file ... 
BUT the results you will get from that are not take for grant. There are 
several problems related to calculating charged states by using Periodic 
Boundary Conditions. The most serious in my opinion is that the infinite 
replication of the charged cell generates an spurious electrostatic background 
- which is partially compensated by introducing a jellium background on the 
calculation ... but it does not  completely vanish - which means that your 
Formation energies will be based on comparing total energies calculated in 
different potential references - which is senseless.


In most of papers I´ve refereed they use a potential aligment procedure to 
`correct` it ... but these aligment procedures are also very questionable. The 
main problem is that the correction ,as it is usually applied, corresponds just 
to an arbitrary shift on the Fermi Energy - i.e. the energy of the free 
electron you have to take into account to calculate the defect ionization 
energy. Thus, it corrects the energy of the electron reservoir which is 
interacting with your system ... but the problem of the mismatching reference 
potentials in you total energy calculations still remains.


Another issue is the electrostatic energy generated by the charged periodic 
replicas ... there is simply no agreement if it must be corrected or not ... 
and even among those who say yes, there few agreement on how.


If you take a look on the literature you will find formation energies of 
Charged Oxygen vacancies in ZnO ranging from -1 to +4 eV ... which clearly 
shows that we still don't have a definitive methodology to handle with charged 
supercells.


In conclusion : Thats a very tricky subject!


NH        


On Mon, Feb 7, 2011 at 12:59 PM, Slimane Haffad <[email protected]> wrote:






hi neyhmor,
 
thank you very much for your quick response and  for the links you gave me, I 
already read some papers, but what i want to know exactly as follows: for the 
calculation of the energy of an transition level (0 / q), we must find the 
energy of the system in the neutral charge state (0)  and the enrgy at charge 
state (q), it is the latter that intrigues me, is this energy that of the 
defect level or it must change few things in the input file of siesta and 
recalculate the energy? 


 
slimane;
 
--- En date de : Dim 6.2.11, N H <[email protected]> a écrit :


De: N H <[email protected]>
Objet: Re: [SIESTA-L] semi metalic caracter
À: [email protected]
Date: Dimanche 6 février 2011, 21h36


The answer for the first question is : No 


For the second you can take a look on:


Van der Walle CG, Neubauer J J. App. Phys 2004 95, 3851.


Janotti, A.; Van de Walle, C.G. Phys. Rev. B. 2007, 76, 165202.


Lany, S.; Zunger, A. Phys. Rev B 2008, 78, 235104.


Makov, G.; Payne, M.C. Phys. Rev. B 1995, 51, 4014-4022. 


Lany, S.; Zunger, A. Phys. Rev. B 2005, 72, 035215.


Lany, S.; Zunger, Phys. Rev. B, 2010, 81, 113201.


Gerstmann, U.; Deak, P.; Aradi, B.; Frauenheim, Th.; Overhof, H. Physica B 
2003, 340, 190-194.


Moreira, N. H.; Aradi, B.; Rosa A. L.; Frauenheim, Th. J. Phys. Chem. C 2010, 
114, 18860-18865. 


>From the beginning be aware that calculating charged defects is a very tricky 
>subject!





On Sun, Feb 6, 2011 at 5:02 PM, Slimane Haffad <[email protected]> wrote:






 
Dear siesta users:
 
I calculated the band structure of nitrogen doped ZnO nanowire and showing a 
acceptor defect level just above the highest occupied state, knowing that the 
Fermi level is below the highest occupied level. I want to know if this looks 
like a semi-metallic character and how to calculate the energy of the system at 
charge state q (-1) in siesta.
I'll be very grateful if someone can help
 
slimane, 






      

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