try:
var=`date`
echo $var
then read the man page for date for more specifics on format.
__ _
Jacob Martinson | Debian GNU/ / / (_)__ __ ____ __
[EMAIL PROTECTED] | / /_/ / _ \/ // /\ \/ /
http://www.ccsi.com/~jacko | /___/_/_//_/ ___/ /_/ _\
[EMAIL PROTECTED] |
On Fri, 2 Jul 1999, Brandon W. Beasley wrote:
> It's GOT to be simple, but I can't figure it out.
>
> I just want to pass the current date to a variable in a bash script.
>
> Do I use the 'date' command? How do I pass output from the 'date'
> command to a variable, say $DATE,
> in a bash script?
>
> thanks
>
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