On Donnerstag, 15. November 2018 22:11:02 CET Guido Trentalancia wrote: > Yes, that is equivalent to a double free operation, i.e. an attempt to free > memory that has not been previously allocated.
A double free is calling free twice on the same valid! pointer. "or corruption" is the case here, tmp is an invalid pointer. -- Stefan Brüns / Bergstraße 21 / 52062 Aachen home: +49 241 53809034 mobile: +49 151 50412019
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