Question #179709 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/179709
Status: Answered => Open
Vinay Kulkarni is still having a problem:
All instances of application have same title. That’s why I am trying to
create instance. I was looking at getting process id from windows os. Is
there any method in python to get process id of app?
Thanks & Regards,
Vinay Kulkarni
Ishnatek Systems & Services Pvt. Ltd.
Contact : +91 8956345939
-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf Of RaiMan
Sent: Wednesday, November 23, 2011 3:01 PM
To: [email protected]
Subject: Re: [Question #179709]: How to open any application from user defined
path
Your question #179709 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/179709
Status: Open => Answered
RaiMan proposed the following answer:
as already mentioned in our private conversation:
--- App.open()
cannot be used in your case, since it does not allow, to specify a start
directory
--- os.popen()
can be used in combination with Window's start command, to start your app from
one of your configuration directories, but it does not return an App instance,
that can be used later
--- window title for app switching
If your different app instances do not have different window titles, you will
not be able, to switch between these apps using Sikuli's switchApp() or
App.focus().
If they have different window titles, use switchApp().
--- other possibilities
if the app window content makes them distinguishable, you might look for this
and use alt-tab to switch the apps. Or you might use clicking the task bar to
switch between the app instances, since they should stay there in the order
they where started.
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