New question #222218 on Sikuli:
https://answers.launchpad.net/sikuli/+question/222218
All I want to do in this script is just open a windows explorer window to a
specific directory so that I can then use the IDE to interact with specific
files to right click etc..
before I do that I just want to open "C:\tssmoketest\2014\"
there are several files in here I need to right click on to go to properties
etc and i can handle that portion fine.
in my script I have:
import os
import subprocess
tsVersion = input("Enter your version ie.. 2013, 2014 etc:", "2014")
subprocess.Popen('explorer os.path.join('c:', os.sep, 'tssmoketest',
tsVersion)')
this doesnt work as my formatting is incorrect.
So i try to get basic with it and just use:
subprocess.Popen('explorer "C:\tssmoketest\2014"')
and this works however it just keeps opening my local user profile documents
folder and I dont know why this is.
I then try to use:
os.system('start "C:\tssmoketest\2014"')
and all this does is open a command line terminal with the file path c:\program
files (x86)\Sikuli X>
I'm still learning python and reading here and there to learn on the fly so my
apologies for the poor coding. Defintely putting notes in my scripts to help
retain and learn along the way.
I didn't think just opening a specific windows directory in windows explorer
woudl be so hard.
I can do it another way which is:
type('r', KeyModifier.WIN)
wait("Typethenameo.png")
paste(os.path.join('c:', os.sep, 'tssmoketest', tsVersion, 'data01'))
type(Key.ENTER)
but its longer and its ugly and figured I could use somethign similar to
someapp.open()
Any help is much appreciated.
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