Hi Marshall,
I found this formula for making Lugol's and wondered if you would vet it.
How to make Lugol's Iodine
Lugol's solution consists of
1. *5 g iodine (I2)* and
2. *10 g potassium iodide (KI)* mixed with
3. *85 ml distilled water*, to make a brown solution with a total iodine
content of 130 mg/mL.
To make the original version, we use what amounts to a 3% (2.91%)
formula (iodine and iodine compound). The formula is simple: 80 gm. of
potassium iodine (KI) is added to 4,000 ml of distilled water (roughly
4,000 gm). After fully dissolving, 40 gm. of iodine crystal is added.
After the iodine crystal fully dissolves (which takes several hours),
the product is packaged and stored.
To make the newer 7% Lugol's version, using the same 4,000 ml. of
distilled water, the amounts of iodine use are 200 gm. of KI, and 100
gm. of iodine crystal. For 15% Lugol's, to 4,000 ml. of distilled water
we dissolve 480 gm. of KI and 240 gm. of iodine crystal.
Potassium iodide renders the elementary iodine soluble in water through
the formation of the triiodide (I3-) ion. It is not to be confused with
tincture of iodine solutions, which consist of elemental iodine, and
iodide salts dissolved in water and alcohol. Lugol's solution contains
no alcohol.
Thanks,
Craig