In a message dated 00-04-11 09:07:39 EDT, you write: << Subj: Re: CS>long and winding oxides Date: 00-04-11 09:07:39 EDT From: [email protected] (coyote) Reply-to: [email protected] To: [email protected] My apologies, I take a deep breath and a start over with more respect. What I see is a black coating on one of the rods, sometimes on the glass between the rods with a varience of color ranging from black to brown to yellowish with the black directly under one rod and the yellowish stuff directly below the other but only really visible if the glass is lit from the bottom. If I stir it up, the water turns the average color of the coating on the glass, usually brownish yellow. What I see if I make a batch mof CS that has a color is that the color, be it yellowish or brownish or even black will deposit on the glass of the container after being left undisturbed for several days or weeks. I can post a photo. The remaining liquid is clear with a good T.E. and strong metallic flavor as before storage, though perhaps not quite as strong. If I place h202 onto that color smear, it vanishes. I presume silver oxides because silver oxides have a dark color [or so I believe from handling dental and photographic waste] and find references to various silver oxides being formed under those conditions. I find no reference to the range of possible colors. I have had experience in the distant past with electroplating gold, lead, copper and zinc and seen what various amperages do to the finish. [rough and burnt looking to smooth and shiny] This CS thing is a bit different but somewhat related. What is it that I am looking at? >>
Any metal will appear black if its particle size is small enough and probably within a range of colors for a variety of particle size distributions. Using color for identification purposes is fraught with difficulties UNLESS you have confimed the type of substance by other means FIRST and through experience with the identical process and materials you generate "mental correlations". As far as oxidizing silver is concerned, someone who has the data can calculate the standard free energy of reaction for, 2Ag + H2O2 ----> Ag2O + H2O You will need the standard free energy of formation for H2O2, Ag2O, and H2O to do the math. I don't have the data, but my guess is that the reaction produces A LOT of negative free energy, i.e., it goes to to the right quite easily. Roger Altman -- The silver-list is a moderated forum for discussion of colloidal silver. To join or quit silver-list or silver-digest send an e-mail message to: [email protected] -or- [email protected] with the word subscribe or unsubscribe in the SUBJECT line. To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
