Hey Bill,

Now there's a trap for young and old ;-)

The silver liberated is independent of the amount of water it is
liberated in. Total milligrams of silver (by your figures) per litre of
water is .32 which is 0.32ppm.
0.32mg into 0.5L is 0.64ppm.

Regards
Ivan.

----- Original Message -----
From: "Bill Schramm" <[email protected]>
To: <[email protected]>
Sent: Thursday, 8 June 2000 03:32
Subject: Re: CS>COULD SOMEONE PLEASE GIVE ME THE FORMULA FOR AMPS PER SQ
CM OR


You can figure out an outside limit (ideal case assuming 100%
efficiency) for silver production from basic chemistry principles.

A few terms:
MOLE:  a very large standard number of atoms or molecules, such that the
weight of one mole of a substance is equal to the atomic or molecular
weight in grams. The atomic weight of Silver is approximately 107.
COULOMB:  the standard unit of electrical charge.  One mole of electrons
has a charge of approximately 96,500 coulombs.
AMPERE: the standard unit of electrical current, or rate of moving
charge.  One coulomb per second is defined as one ampere, or Amp.  1 Amp
= 1000 Milliamps.

If you are running a constant current process, you can calculate this
limit simply:

number of grams of silver = multiply current in amps  times  time of the
process in seconds  Divide by 96,500 to get moles of electrons.  Since
silver is singly ionized, then multiply by 107 to get the number of
grams of silver.  Compute ppm weight by assuming that 1 liter of water =
1000 grams.   1  ppm = 1 milligram per liter.

Example:  current = 1 milliamp    time = 5 minutes   amount of water =
1/2 liter
      by the above math then:
                total coulombs = 0.3
                total moles = .00000310 (3.10 micromoles)
                total grams of silver = .00032 (0.32 milligrams)
                total grams of silver per liter  .00064 (0.64
milligrams)
                parts per million by weight  0.64

If you are running a constant Voltage process, it is more complicated.
The silver production is a function of current, not voltage.  The
voltage produces current according to ohms law (voltage divided by the
resistance of the circuit).  The problem is the resistance of the
distilled water is constantly changing, since the CS you produce lowers
the resistance.  Technically you would have to integrate the current
over time, in practice you can estimate in blocks with measured
resistance or current.

Also remember this is a THEORETICAL UPPER LIMIT for silver production,
not a prediction of actual production values.




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