In a message dated 12/12/00 12:51:35 PM EST, [email protected] writes: << Subj: Re: CS>Progress report w/ingot Date: 12/12/00 12:51:35 PM EST From: [email protected] (Marshall Dudley) Reply-to: [email protected] To: [email protected] We went through all this about a month ago. What is important is the density of particles near the electrode times the length of time they are there. When this factor goes up, the size goes up. Increasing voltage causes the particles to move away from the electrode through elecrtophrosis faster reducing the density. Increasing current density causes more particles to be generated per unit of time, increasing the density. So we have particle density is proportional to current/voltage. Aggregation will be proportional to this and the length of time they are in a high density area, ie. time*current/voltage. For all practical purposes the voltage and current elements cancel out, leaving time, and time near the electrode is inversely proportional to voltage, with current having minimal effect. Thus density*time will be proportional to current/voltage^2, and since current is proportional to voltage, we get that the density*time, or aggregation constant, is proportional to 1/voltage. With all else equal, particle size drops with increasing voltage. I have verified this many times with HVAC process. I am assuming the same rules apply in the LVDC process, but have not experimentally verified it. Marshall >>
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