Ian:
http://www.silvermedicine.org/conversion%20form.html
This is another version of the form:
By adding 1.4229 ounces of your 35% Solution1 ( H2O2 ) to 15.177100000000001
ounces of distilled water or colloidal silver ( Solution2 ), you will
achieve 16.6 ounces of a 3% end solution.
The algebraic equation:
( S1*X) + ( S2*(z-x)) = S3*Z
X = amount of H2O2 to use
Z - X = amount of distilled water to use
S1= your h2o2 strength
S2=your h2o2 strength in the distilled water ( in this case, ignored for it
is zero )
Z= The amount of your end solution ( ie the 16.6 ounces )
S3= Ending strength of H2O2
(.35 X ? ) + ( 0 X ( 16.6 - ? ) = .03*16.6
.35X + 0 = .498
-------------------- = 1.4229 ounces
.35
You can, of course, substitute milliliters throughout the equation.
Kind Regards,
Jason
----- Original Message -----
From: "Ian Roe" <[email protected]>
To: <[email protected]>
Sent: Wednesday, December 04, 2002 7:24 AM
Subject: Re: CS>Titration Math
> Hi:
>
> Yes but if I do this, I have to mix it up in a separate container and
repour
> etc. I was trying to avoid this. I was trying to determine how much 35%
to
> put in the bottle to start with so I wouldn't have to mix and repour.
>
> Ian Roe
>
> ----- Original Message -----
> From: "Dean Miller" <[email protected]>
> To: <[email protected]>
> Sent: Tuesday, December 03, 2002 6:07 PM
> Subject: Re: CS>Titration Math
>
>
> > On Tue, 3 Dec 2002 15:53:45 -0500, "Ian Roe" <[email protected]>
> > wrote:
> >
> > >Can someone here show me the formula for dilution. I knew how to do
this
> once but I just can't remember now.
> > >
> > >Problem: wish to put an unknown volume of 35% H2O2 into a 250 ml and a
> 500 ml container and fill with distilled water to obtain 3%.
> >
> > If you're not too picky (IOW, you want something close to 3% and
> > aren't using it for quantitative analysis), and since H2O2 and water
> > have about the same weight per volume -- just mix 1 part H2O2 with 11
> > parts of water. That'll produce about 3% H2O2. (A 1/9 mixture will
> > be 3.5%).
>
>
> --
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