url: http://escribe.com/health/thesilverlist/m60429.html
CS>Mike M.'s process questions...
From: M. G. Devour
Date: Thu, 19 Jun 2003 19:18:34

  >> Three feet of 12 ga wire cut in half should give about 3.8 square
  >> inches of wetted area for the anode and cathode. I run at 335 uA,
  >> so the current density is around 87 uA/sq. in.

  > Ummm, just  to  relieve me of digging out the  calculator  at this
  > late hour... You're not counting the surface are of both the anode
  > and cathode together, are you? Only the anode surface area counts,
  > right? And that's ~ 3.8 in^2?

  > Mike D.

  You don't even need a calculator for this one. 12 ga has  a diameter
  of 0.080 inch. The circumference is pi * d = 0.25 inch, so  4 linear
  inches gives 1 square inch. But you knew that already.

  If you cut three feet in half, each half is 18 inches. When you form
  them into  a "W", you need about an inch clearance  to  the mounting
  screws, and  about 3/8 inch for a tiny wrap around the  screw.  So a
  bit less than 16 inches is under water. I estimate this  gives about
  3.8 square inches of wetted area. It's not exact, but  close enough.
  It affects  only  the  current density, and  has  no  effect  on the
  calculated ppm.

  Since both  electrodes  have  the same area,  I  use  either  one to
  calculate the wetted area.

  In operation, an ion cloud forms around both electrodes.

  Theoretically, the  anode  could  have  a  bit  less  area  than the
  cathode, but  both  clouds   are   important   in  the  formation of
  particles.

  The anode  cloud will be slightly less dense than the  cathode since
  the ions are moving away from the anode towards the cathode.

  You can  see this effect by running the current density  high enough
  to start  misting.  The mist appears first at  the  cathode,  then a
  while later at the anode. But both electrodes will eventually form a
  mist. At least, this has been my experience.

  In practise, I may get a slight amount of residue on the  anode. Not
  enough to  write home about, especially compared to  the  heavy film
  that always formed at 1.4 mA/sq.in, and the black deposit under each
  electrode on the bottom of the glass.

  The curious thing is when I switch the anode and cathode electrodes,
  the black  residue  on the new cathode gets cleaned  off.  I believe
  Steve observed the same thing.

  But there is no deposit on the bottom of the glass, and it stays clean.

Best Regards,

Mike Monett


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