url: http://escribe.com/health/thesilverlist/m60633.html
CS>Re: Long, Boring - Calculations
From: AScottSilver
Date: Mon, 23 Jun 2003 22:05:05
> Hi Mike,
> Thanks for the response. Regarding your mold problems - MOVE. Go
> to Phoenix or somewhere like that.
[...]
> So to rehash:
> One quart production in about 6 to 10 hours.
> 3 feet of 12 ga. wire to work with.
> Probably a resistor for current limit.
> Stirring can be added later.
> 9V battery stack or 12VDC wall transformer.
> Plastic lid and hot glue.
> I can tell them an approximate run time or I can tell them to shut
> it off when the electrodes turn black. Any more than that would be
> rocket science.
> What do you think?
> Andy
Hi Andy,
This is where a program like Mercury really comes in handy.
http://escribe.com/health/thesilverlist/m60493.html
First we enter the conversion factors:
C = I * sec ; total number of Coulombs
den = I / sqin ; current density Amperes per sq in
gm = k * I * sec ; Faraday's equation
k = 107.88 / 96500 ; Coulombs required per gram of silver
lt = qrt * 0.946 ; convert quarts to litres
mg = gm * 1000 ; convert grams to milligrams
ppm = mg / lt ; 1 ppm is 1 milligram per litre
sec = hrs * 3600 ; convert hours to seconds
Then we see how long it would take to make 2 quarts of 20 ppm cs at
87 uA/sq.in.
We enter the desired parameters and let Mercury solve the unknowns:
ppm = 20 ; desired ppm
qrt = 2 ; volume in quarts
sqin = 3.8 ; wetted area of 12 ga wire
den = 87e-6 ; current density in Amp/sq.in.
The answer is to brew at 330 uA for 28 hours:
hrs = +28.44
I = +0.000330
This is too long, so we see what current is needed for a 10 hour
brew time. We enter the desired parameters:
hrs = 10 ; desired brew time in hours
ppm = 20 ; desired ppm
qrt = 2 ; volume in quarts
sqin = 3.8 ; wetted area of 12 ga wire
It would take 940 uA, and the current density is 247 uA/sq.in.
den = +0.000247
I = +0.000940
This might be near the critical current where it starts misting and
generating particles. I don't know where the threshold is.
Let's try setting the current density to 200 uA/sq.in. and let it
tell us the current and brew time:
ppm = 20 ; desired ppm
qrt = 2 ; volume in quarts
sqin = 3.8 ; wetted area of 12 ga wire
den = 200e-6
Now it takes 760 uA for 12 hours:
hrs = +12.37
I = +0.000760
This might work, and it's not too far from your original goal.
So what you'd need is a LM134 supplied with with perhaps 15V or
higher, or a resistor going to a fairly high voltage.
You can play with it and see what would meet your needs.
Best Regards,
Mike Monett
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