Wayne,
The way I understand it is that Faraday determined that the amount of metal released from the anode
during electrolysis is proportional to the current flowing thru that electrode and the time that
that current flows. Different metals would have different values for "k" but for any particular
metal the value in the equation is a constant.
Faraday’s equation for electrolysis:
m = k*I*t
where:
m = mass in grams
k = electrochemical equivalent = 0.001118
I = current in amps
t = time in seconds
This formula tells us exactly how much silver was liberated from the electrode (anode) and is
determined by k = a constant, I = current, and t = time.
[“k”, the electrochemical equivalent, is derived from the chemical equivalent for silver which is
the atomic weight in grams of silver divided by the valence number times the number of coulombs
(ampseconds) required to liberate this amount of silver]
See my re-post of the "Calculations for Making Colloidal Silver" message (which should follow, or
precede, this message depending on the idiosyncrasies of the various e-mail/internet systems...)
Dan
-------------------------------------------
* From: * CWFugitt[SMTP:[email protected]]
* Sent: * Sunday, November 19, 2006 12:50:08 AM
* To: * [email protected]
* Subject: * Re: CS>Re: FW: CS>Mink rancher
Morning Dan,
At 10:54 PM 11/18/2006, you wrote:
>Even if the water flow is different, you can still calculate the
>amount of liberated silver in the batch based on the amp-seconds.
Can you explain the Faraday method a bit more?
Is it a form of wattage calculation that controls the amount of silver
removed from the electrode?
Even though it is a bit primitive, one can get flow rates very close
with a stop watch and a vessel of known size.
In the absence of a flow meter, it is about the only choice.
Wayne
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