On 2015-12-24 02:02, Will Senn wrote:
On 12/23/15 5:09 PM, Johnny Billquist wrote:
As for your analysis:
Your explanation of branches seems somewhat over complicated. The
instruction is indeed in just 8 bits, while 8 bits are the offset.
However, there is no need to mess things up with one-complement, or
tricks like that. The offset is an 8-bit value. Sign extend to 16
bits. Multiply by 2, and add to the updated PC. Simple as that.
(Note that I said "updated PC". The PC will contain the address of the
instruction after the branch before you start doing the calculation
for the branch destination.)
Johnny,
Given Line 7 037760 100376 BPL WAIT
100376 is a BPL instruction and the offset (376) is to be multiplied by
two and added to the updated PC. That is, 376 * 2 is going to be added
to 037762. 376 represents a negative offset in two's complement notation
- it has a one in it's most significant bit, the left hand bit in 11 111
110. As a human, I kind of need the number in some form that makes sense
to me, so I convert it to a positive quantity by first taking the one's
complement and adding one. This gives me the positive magnitude of the
negative number -1. Multiplying this by two is easy, it's -2, which when
added to 037762 yields 037760 , which is the correct location. This is
how I did the math. If I understand you correctly, the machine doesn't
do it this way. I tried multiplying 376, 11 111 110 by shifting left
one, 11 111 100, and adding that to 037762's binary representation, but
that doesn't seem to make sense. Would you please elaborate?
Sure.
376 in twos complement is -2. (Sign extended it will still be -2, but
that will then be 177776)
Multiply that by 2 gives -4.
The branch is at address 37760. The updated PC will be 37762 after the
branch instruction have been fetched by the CPU. So the branch will be
to 37762 - 4, which is 37756.
Johnny
--
Johnny Billquist || "I'm on a bus
|| on a psychedelic trip
email: [email protected] || Reading murder books
pdp is alive! || tryin' to stay hip" - B. Idol
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