Raymond Dans wrote: > As part of resolving XECS-1852 - "remote invocation of yum update > through sipXsupervisor", I need to launch a Python script that resides > in the SipX bin directory. I, obviously cannot hard code the path to > this location and SipXecsService does not provide a way of obtaining it > either. Based on the paths that SipXecsService provides today, it > doesn't look like this type of path should be added here either. > > Is there a recommended programmatic method of obtaining this path from > C++ or should I add it to the sipxsupervisor-config file and then obtain > it from the Configuration Database? > > Thanks in advance > Raymond
Why not determine it during compile time like all the other paths? D. _______________________________________________ sipx-dev mailing list [email protected] List Archive: http://list.sipfoundry.org/archive/sipx-dev Unsubscribe: http://list.sipfoundry.org/mailman/listinfo/sipx-dev
