Thanks a lot Antony, it was really as simple as this.
MARENDY, Anthony wrote:
Try the getChildResources() method. This will return a WebDavResources object
which you can then iterate through.
For each WebDavResource contained therein, you can call the isCollection()
method to determine if it is a collection or not.
Anthony.
-----Original Message-----
From: Vladimir Sakhovski [SMTP:[EMAIL PROTECTED]
Sent: Wednesday, 15 March 2006 18:05
To: [email protected]
Subject: Problem with list()
Hello, I have a newbe question, which puzzles me for the last 2 days. In
my simple webdav client application call to list() on a WebdavResource
object returns an array with names of all files on a current path and
the name of a current directory, but no subfolders in it. For example,
if I have a folder "folder01" with "file01", "file02", "subfolder01",
and "subfolder02", when list() will return an array with "file01",
"file02" and "folder01" in it, and not "file01", "file02",
"subfolder01", "subfolder02", as I expected.
Client bundled with slide distribution shows the same behaviour. So my
question is, do I miss some important point about webdav interaction,
and what would be the right way to learn correct file structure on a
webdav server?
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--
Vladimir Sakhovski
Software Developer
www.iplabs.de
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